急急今天晚上作业"求(2+1)(2^2+1)(2^4+1)(2^8+1)的组"平方差公式做

乘以1=2-1

所以(2+1)(2^2+1)(2^4+1)(2^8+1)
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1

=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)/(2-1)
=(2^2-1)(2^2+1)(2^4+1)……(2^8+1)/1
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1

=(2+1)(2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1
这种题目只要这样一步步推就行了。。实在不放心可以死算验算下。。

令原式=S
s=[s*(2-1)]/(2-1)=(2^16-1)/(2-1)=2^16-1